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səhifə | 424/489 | tarix | 03.01.2022 | ölçüsü | 18,33 Mb. | | #50422 |
| u = 4.47 N/cm2 ; σ′ = 23.30 + 2.23 = 25.53 N/cm2 ;
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σ = 30 N/cm2 and ∆V/V = 3.23% (from curve)
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o
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At the beginning of the 2nd stage of construction, (1b on Fig. 15.23)
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(∆V
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/V ) = 3.23% ; u
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1b
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= 4.47 N/cm2, σ
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= 25.53 N/cm2 and σ
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= 30 N/cm2
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1b
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o
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1b
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1b
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p
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ob
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= p ( = p
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atm
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) + u = 10.3 + 4.47 = 14.77 N/cm2
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o
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Sob =
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So
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F
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po
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1 + G
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− 1J
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(1 − So + So H)
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H pob
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K
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=
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0.80
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= 0.853
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F
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10.3
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I
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1 + G
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− 1J (1
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− 0 . 8 + 0.8
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× 0 . 02)
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H 14.47 N
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K
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F
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I
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∆V
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∆V
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nob = no
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+
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1b
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= 0.375 – 0.0323
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Gas
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1b
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is
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− veJ
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Dostları ilə paylaş: |
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