Contents preface (VII) introduction 1—37



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Fig. 17.9 (a and b). Variations of coefficient of dischrge for ogee spillway (Contd...)



576 IRRIGATION AND WATER RESOURCES ENGINEERING





Modified




C



C



1.00










hO




0.90

hd




HO










P

d










0.80










0.76

1.1

1.2

1.3

1.4

1.5

1.6

1.7

1.8




1.0




(ho + d)/Ho
(c) Ratio of discharge coefficient due to apron effect








1.0





































0.8





































0.6
















hO







hd








































/C
















HO










d







S


































C

0.4













P

















































0.2





































0





































0

0.1

0.2

0.3

0.4

0.5







0.6

0.7

0.8



















hd /Ho

























(d) Ratio of discharge coefficient due to




tailwater effect







1.1





































1.0


































0




























ha







C/C
















HO
















0.9













H

e






























































































P






















0.8





































0

0.2

0.4

0.6

0.8

1.0

1.2

1.4

1.6



















He / Ho























(e) Coefficient of discharge for Ho other than the design head


Fig. 17.9 (c, d and e) Variations of coefficient of discharge for ogee spillway (4)
Example 17.3 Obtain USBR profile for an ogee spillway with the following data:
Design discharge = 13875 m3/s
Crest length of spillway = 183 m
Crest level of spillway = 203.34 m
River bed level = 166.50 m





SPILLWAYS













577




Solution: Assuming C = 2.20 in Eq. (17.5), one obtains










L

13875

O

2 /3







Ho = M




P

= 10.59 m



















N

183 × 2.20 Q







and

P = 203.34 – 166.50 = 36.84 m






P
















= 3.48










Ho










From Fig. 17.9 (a), C = 2.18
With C = 2.18, Eq. (17.5) yields H0 = 10.655 m
Design head for spillway profile = 0.75 × 10.655 = 7.99 m ~ 8.00 m (say)









P

36.84

























=










= 4.605







Ho

8.00










Approach velocity, va =










13875




= 1.69 m/s































183 (36.84




+ 8.00)
























ha = 0.15 m

and




ha/Ho = 0.019




From Figs. 17.8 (b) and (c), k = 0.504

and n = 1.861



Hence, the profile of the ogee spillway, [Fig. 17.8 (a)] is given by



y







L

X O1.861







=

− 0504.

M




P




8.00













N

8.00Q





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