Contents preface (VII) introduction 1—37



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Fig. 17.12 Shaft spillway
Depending upon the type of crest, the shaft spillway can be either standard-crested or flat-crested (Fig. 17.13). In a standard-crested spillway, the water begins its free fall immediately upon leaving the crest whereas in the flat-crested spillway water approaches the crest on a flat slope before beginning its free fall. The standard-crested spillway would have a smaller diameter crest since its coefficient of discharge is greater than that of a flat crest. Therefore, if the shaft spillway is to be constructed in the form of a tower, it would be economical to have a standard-crested spillway. However, a flat-crest shaft spillway has a smaller funnel diameter and is, therefore, more advantageous when the spillway is to be excavated in rock. The design of a standard-crested shaft spillway has been discussed here.
The design of a standard-crested shaft spillway involves the determination of the funnel radius, R, and the head over the theoretical sharp crest, H, for known discharge, Q and the allowable maximum head, h on the spillway crest (Fig. 17.14). The method given by Creager, et al. (6) is valid for negligible velocity of approach and involves trial at two stages and is based on the following equations:

582 IRRIGATION AND WATER RESOURCES ENGINEERING

Funnel





Funnel

Crotch
















Standard-













crested spillway













Free-falling




shaft

section




section




Vertical

Verticalshaft







Crotch




section

Vertical

shaft







Vertical













shaft












H.W.S.


Weir section
Free-falling

section
Flat-crested



spillway




Fig. 17.13 Standard-crested and flat-crested profiles for shaft spillway


H h Spillway crest





x




Theoretical







sharp crest







R







Top of boil

spillway













L







C




Crotch







y








Fig. 17.14 Jet profile over standard-crested shaft spillway





SPILLWAYS










583







Q = 2 π RC1

g H 3 / 2

(17.9)







r




H













= 0.11 – 0.10







(17.10)







H

R







H = h + r










(17.11)





In these equations, C1 is the coefficient of discharge which is related to H/R as shown in Fig. 17.15, and r is the rise of the lower nappe above the theoretical sharp crest. The different steps involved in the trial method are as follows:



0.61


0.60

0.59


0.58
C1
0.57

0.56


0.55

Boil


C1



25







20







15boil




10

oftopof




y/H










5

Ordinate










0







–5







0

0.1 0.2 0.3 H/R




0.4

0.5


Fig. 17.15 Variations of C1 and the ordinate y/H of the top of boil for standard-crested shaft spillway (6)
(i) Assume some suitable values of H and R and, hence, H/R, and obtain the value of C1 from Fig. 17.15.
(ii) Determine the discharge intensity, q per unit length of the crest, i.e.,


q = C g H 3 /2

(17.12)

1




(iii) Obtain the required radius R from


R =

Q

(17.13)




q












Compare this value of R with the assumed value of R in step (i). If these two values do not match, assume another value of R for the same assumed value of H and re-peat the procedure until the value of R obtained in step (iii) matches with the as-sumed value of R.


(iv) Determine r from Eq. (17.10) and then obtain h from Eq. (17.11). If this value of h does not agree with the given value of h, one has to assume another value of H, and repeat steps (i) to (iv) until the agreement is reached.



584 IRRIGATION AND WATER RESOURCES ENGINEERING
Vittal (7) has obtained a direct solution for R and H by rewriting Eqs. (17.9) to (17.11) as follows:
From Eq. (17.9),




Q* =










Q










= 2π







R

C

F

H

I 3 /2

(17.14)
















1/ 2




5 /2




























g

h


































h










1G




J















































































H

h K
















Using Eq. (17.11), Eq. (17.10) can be rewritten in the following two forms:










r

=




H h

= 1 −

h




= 0.11 − 0.10

H













H










H




H

R




















































































h

= 0.89 + 0.10




H





































(17.15)







H







R


























































































































































r










H h
















H


















h



















H


























































= 0.11 − 0.10







and




=




=










R







R







H










H






















H
















R

































































































F H I 2





































R



































































H


































h

































G







J

+ 8.9













− 10






















= 0




(17.16)










R
















R










H R K





















































































From Fig. 17.15, and Eqs. (17.15) and (17.16), one obtains the following functional




relationships:





































F H I



































































































































































C = f1G







J





























































































































































1










H

R K















































































h













F

H I





















































































=

f2 G










J












































































H






























































































H

R K












































































H

=

f

F

h

I






































































































































































R

3 G










J



























































































H

RK




















































Using the above functional relationships, Vittal (7) obtained the following functional relation:








F

H I

3 /2

F

h I




























C1G







J

=

f4 G




J
















(17.17)








































H




h K




H

RK






















Actual relationship of Eq. (17.17) can be obtained by obtaining C1 from Fig. 17.15, the




values of

h

from Eq. (17.15), and




h

from Eq. (17.16) for different values of

H

ranging from



















R




H




R






















F

H I 3 /2

F

h I














































0 to 0.5. One can, therefore, prepare a curve of C1G

J

versus G




J . Vittal (7) obtained the








































H

h K

H

RK













following equation for this curve:


































C

F

H

I 3 /2

= 0.6988 − 0.0882 F

h

I

− 0.296 F

h

I 2

(17.18)
















1G




J

G




J

G




J










H

h K

H

RK

H

RK







On combining Eq. (17.18) with Eq. (17.14), and solving the resulting quadratic equation, one obtains,

SPILLWAYS


F

RI

2

R










G




J

− (0.2280 Q* + 0.1263)




− 0.3861

= 0







h




H

h K



















R

L







14432.









= (0.1140 Q* + 0.0632) M1

+

1 +

(0.2280 Q + 0.1263)2




h










M







*










N














O
P
PQ




585

(17.19)



For large values of Q* (say, greater than 25), Eq. (17.19) can be approximated to





R

= 0.2280 Q + 0.1264










(17.20)







h
















*































For known Q and h and, hence, Q , one can easily determine

R




(and, hence, R) from one

























*







h
























































































H




of the Eqs. (17.19) and (17.20). Using Eq. (17.16) one can determine







and, hence, H. For







R




example, values of Q and h equal to 851.2 m3/s and 3.05 m, respectively, yield










Q* = 16.73


































R

= 4.03



R = 12.29 m

















































h






















H




= 0.27



H = 3.325 m

















































R
















The profile of the underside of the nappe over the circular sharp-crested weir can be determined from Fig. 17.16 which enables computation of x for a given value of y , and already computed R and H. If R0 is the radius of the lower nappe at any given elevation y, then

R0 = R x
And x0, representing the value of x for the upper side of the nappe at a given value of y, is obtained from (6)




x




= R

R 2






Q

(17.21)




0
















0




π

2 g(y + 1269. H)



























Here, y + 1.269 H is the head available for vertical velocity. Proceeding in this manner, one can compute the value of x and x0 for different values of y until x0 equals R at which value of y the horizontal velocity ceases and its energy gets converted into a ‘boil’ as shown in Fig.




  1. The ordinate Hy of the top of the boil can be computed from the curve shown in Fig.




  1. The point at which x0 becomes equal to R is usually known as ‘crotch’. The above analysis does not include the friction loss as it is difficult to be considered and is within permissible limits for the accuracy desired (6).


The diameter of the vertical shaft below the crotch continues to decrease until the size becomes such that the discharge, Q can be carried according to the head available. The radius of the transition shaft, R′ at a given elevation y is obtained from



Q = π R 2 2gh

(17.22)

v




in which, hv = y + 1.269 H hL1 hL2
where, hL 1 and hL2 are the head losses due to friction, respectively, from the crest to the crotch and from the crotch to the elevation under consideration.



586
0.0
Crest of

theoretical weir







1







2







3




Valuesofy/H

4




5









6


7

8


9

10

0


IRRIGATION AND WATER RESOURCES ENGINEERING
























50.0







Values




45.0
















of
















40.0







H/R













=































0
















.
















0




35.0







.

0










.










0

0

10



















30.0

15







.







20










































1 2 3 4 5


Values of x/H




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