197. A=(G+S) holatda umumiy vodorod bog`lar soni 126 ta
bo`lsa DNK fragmenti uzunligini aniqlang.(qo`sh. Nuk.
Orasidagi
masofa 0.34nm)
A)18,36 B)36,72 C)35,7 D)17,85
Ishlanishi:
1) 2A+3G=126
A=2G
2) 2*2G+3G=126
7G=126
G=18
3) 2A+3*18=126
2A=126-54
2A=72
A=36
4) (A+G)*0,34nm=(18+36)*0,34=54*0,34=
18,36nm Javob: A
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198. A=(G+S) holatda umumiy vodorod bog`lar soni 126 ta
bo`lsa, DNK fragmentidagi fosfodiefir bog`lar sonini hisoblang.
A)106 B)103 C)107 D)53
Ishlanishi:
1) 2A+3G=126
A=2G
2) 2*2G+3G=126
7G=126
G=18
3) 2A+3*18=126
2A=126-54
2A=72
A=36
4) (A+G)=(18+36)*2=54N 2N=54*2=108N
5) F=N-2 F=108-2=
106F Javob: A
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199. A=(G+S) holatda umumiy vodorod bog`lar soni 126 ta
bo`lsa DNK dagi A-? T-? G-? S-?
A)A-36 T-36 G-18 S-18 B)
A-18 T-36 G-18 S-36
C) A-36 T-36 G-36 S-36 D) A-18 T-18 G-18 S-18
Ishlanishi:
1) 2A+3G=126
A=2G
2) 2*2G+3G=126
7G=126
G=18
3) 2A+3*18=126
2A=126-54
2A=72
A=36
4) A-T=
36; G-S=
18 Javob: A
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200. A=(G+S) holatda umumiy vodorod bog`lar soni 126 ta
bo`lsa, DNK qo`sh zanjiridagi A-T
orasidagi va G-S orasidagi
vodorod bog`lar farqini aniqlang.
A)18 B)36 C)20 D)24
Ishlanishi:
1) 2A+3G=126
A=2G
2) 2*2G+3G=126
7G=126
G=18
3) 2A+3*18=126
2A=126-54
2A=72
A=36
4) H=2A-3G H=(2*36)-(3*18)=72-54=
18 Javob: A
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