Vo
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H
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Vo
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K
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= 0.343
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Using these values and Hilf’s equation, one obtains
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F
|
∆V12
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I
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G
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J pob
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Vo
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∆u12
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= –
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H
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K
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F
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∆V12
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I
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G
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J
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+ nob (1 − Sob + Sob H)
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Vo
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H
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K
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F
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I
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∆V
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14.77 G
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12
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J
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Vo
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= –
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H
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K
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∆V
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12
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+ 0.343 (1 − 0 . 853 + 0 . 853 × 0 . 02)
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Vo
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F
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I
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∆V
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14.77 G
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12
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J
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= –
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H
|
Vo
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K
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.
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∆V
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12
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+ 0.056
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Vo
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EMBANKMENT DAMS
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521
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|
One can now compute ∆u12 and prepare the following table :
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∆V
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∆V12
|
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|
∆u12
|
Pore pressure
|
σ′
|
σ
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Vo
|
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Vo
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(%)
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=
|
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∆V
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|
−
|
∆V1b
|
|
(w.r.t. 1b as origin)
|
(w.r.t. initial pore pr.)
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V
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V
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o
|
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o
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=
|
∆V
|
|
– 0.0323
|
(N/cm2)
|
= u1b + ∆u12 (N/cm2)
|
(N/cm2)
|
(N/cm2)
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Vo
|
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3.23
|
|
0
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|
0
|
4.47
|
25.53
|
30.00
|
|
4.0
|
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|
0.0077
|
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|
2.35
|
6.82
|
40.00
|
46.82
|
|
4.5
|
|
|
0.0127
|
|
|
4.33
|
8.80
|
54.50
|
63.30
|
|
4.65
|
|
0.0142
|
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|
5.02
|
9.49
|
60.61
|
70.00
|
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|
The values of ∆u12 are shown plotted in Fig. 15.23 from 1b to 2b. Using this figure, a plot of u versus σ can be prepared, Fig. 15.24.
-
30
|
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=
|
u
|
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|
20
|
|
|
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|
u(N/cm 2)
|
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|
|
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|
|
2
|
|
|
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|
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|
10
|
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|
2b
|
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|
1b
|
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|
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|
0
|
10
|
20
|
|
30
|
40
|
50
|
60
|
70
|
|
|
|
|
|
|
(N/cm2)
|
|
|
|
|
Dostları ilə paylaş: |