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səhifə | 14/48 | tarix | 03.01.2022 | ölçüsü | 446 b. | | #48483 |
| Speed-up: - if TS is the best time to process a problem sequentially,
- then the parallel processing time should be TP=TS/P with P processors
- speedup = TS/TP
- the speedup is limited by Amdhal law: any parallel program has a purely sequential and a parallelizable part TS= F + T//,
- thus the speedup is limited: S = (F + T//) / (F + (T///P)) < P
Scale-up: - if TPS is the time to solve a problem of size S with P processors,
- then TPS should also be the time to process a problem of size n*S with n*P processors
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